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∫(\tan x)⋅dx

I:=∫\limits_{0}^{x} (\tan x)⋅dx=?

s:=\cos x
ds=-(\sin x)⋅dx
÷{ds}{-(\sin x)}=dx

I=∫÷{\sin x}{\cos x}⋅dx
I=∫÷{\sin x}{\cos x}⋅÷{ds}{-(\sin x)}
I=∫÷{ds}{-(\cos x)}
I=∫÷{ds}{-s}
I=-∫÷{ds}{s}
I=-\ln|s|
I=-\ln|\cos x|

Author: Danny (remove the ".nospam" to send)

Last modification on: Sat, 04 May 2024 .