∫÷{1}{x⋅\ln x}⋅dx

I:=∫÷{1}{x⋅\ln x}⋅dx=?
u:=\ln x
du=÷{1}{x}⋅dx
x⋅du=dx
I=∫÷{1}{x⋅u}⋅x⋅du
I=∫÷{1}{u}⋅du
I=\ln |u|
I=\ln |\ln x|

Author: Danny (remove the ".nospam" to send)

Last modification on: Sat, 04 May 2024 .